A projectile of volume 367.20000000000005 cm3 is fired from a launcher with an intital kinetic energy of ? - launcher x registration key free
A projectile 367.20000000000005 cm3 volume is introduced by a platform with a kinetic energy of intital
2.12 x 103 kJ. What is the initial velocity of the projectile, in (m / s) terms, if the density of 18.95 g / cm 3
Monday, February 8, 2010
Launcher X Registration Key Free A Projectile Of Volume 367.20000000000005 Cm3 Is Fired From A Launcher With An Intital Kinetic Energy Of ?
3 comments:
Well, that was Trevor on the right track, but made a mistake:
(Projectile mass = 18.95 * 367.2 = 6958.44 g = 6.958 kilograms
Ek = ½ * m * V ²
2120000 = 6958 * v * ½ ²)
It was from the beginning here ... then:
v ² = 2120000x2/6.958
V ² = 4240000/6.958
V ² = 609370.5088
V = 780.62 m / s
For this problem, do not forget the value of volume with more than 4 sig figs. Because it limits the accuracy of the data. With this strange value in its entirety does not affect the final result has
Mass of projectile = 18.95 * 367.2 = 6958.44 g = 6.958 kilograms
Ek = ½ * m * V ²
= 2120000 * 6958 * ½ v ²
v ² = 2120000/3479
V ² = 609.33
v = 24.68m / s
It uses the fact that K = 1 / 2 mv ^ 2 and solve the density = density, from time to c.
I dare not make the computer, because her job, and because the number you have given the volume is very rare - what with all the zeros?
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